Single correct option
Match the entries of List-I with those of List-II.
List-I
P. Number of complex numbers satisfying
Q. Minimum value of over all with
R. Maximum value of over all with
S. Area of the triangle whose vertices are the roots of
List-II
(1)
(2)
(3)
(4)
(5)
List-I
P. Number of complex numbers satisfying
Q. Minimum value of over all with
R. Maximum value of over all with
S. Area of the triangle whose vertices are the roots of
List-II
(1)
(2)
(3)
(4)
(5)
- A. P→5, Q→1, R→4, S→2
- B. P→3, Q→1, R→2, S→4
- C. P→3, Q→5, R→4, S→2
- D. P→3, Q→1, R→4, S→2
Show answer and solution
Answer: (D) P→3, Q→1, R→4, S→2
P: taking moduli, gives or . For , means , giving solutions; with the total is , i.e. (3). Q: the point is at distance from the origin, so the least distance to the unit circle is , i.e. (1). R: for we have , so and ; at we have and the condition is met with , so the bound is attained: (4). S: the roots form an equilateral triangle of circumradius and side , with area , i.e. (2). So P→3, Q→1, R→4, S→2.
Saved on this device. Sign in or create a free account to keep it on every device.