Single correct option
Match the complex ions in List-I with their geometry and magnetic character in List-II (use atomic numbers: Fe 26, Co 27, Ni 28; spin-only formula, BM).
| List-I | List-II |
|---|---|
| P. | 1. Square planar, diamagnetic |
| Q. | 2. Tetrahedral, BM |
| R. | 3. Octahedral, BM |
| S. | 4. Octahedral, diamagnetic |
| | 5. Octahedral, BM |
| List-I | List-II |
|---|---|
| P. | 1. Square planar, diamagnetic |
| Q. | 2. Tetrahedral, BM |
| R. | 3. Octahedral, BM |
| S. | 4. Octahedral, diamagnetic |
| | 5. Octahedral, BM |
- A. P→3, Q→4, R→2, S→1
- B. P→3, Q→5, R→2, S→1
- C. P→4, Q→3, R→1, S→2
- D. P→3, Q→4, R→1, S→2
Show answer and solution
Answer: (A) P→3, Q→4, R→2, S→1
P: is ; is a weak-field ligand, so high spin, , 4 unpaired electrons, BM, octahedral: 3. Q: is ; is strong enough for low spin , 0 unpaired, diamagnetic octahedral: 4. R: is ; chloride is a weak-field ligand, giving tetrahedral geometry with 2 unpaired electrons, BM: 2. S: is a strong-field ligand which pairs the electrons, giving square planar, diamagnetic: 1. Thus P→3, Q→4, R→2, S→1. Option 5 ( BM, one unpaired electron) matches none of the four.
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