Single correct option
Match the complex ions in List-I with their properties in List-II. (Atomic numbers: , , .)
List-I: (P) ; (Q) ; (R) ; (S)
List-II: (1) spin-only magnetic moment ; (2) diamagnetic and square planar; (3) four unpaired electrons; (4) tetrahedral with spin-only magnetic moment ; (5) configuration
List-I: (P) ; (Q) ; (R) ; (S)
List-II: (1) spin-only magnetic moment ; (2) diamagnetic and square planar; (3) four unpaired electrons; (4) tetrahedral with spin-only magnetic moment ; (5) configuration
- A. P→1, Q→3, R→2, S→4
- B. P→3, Q→1, R→2, S→4
- C. P→1, Q→3, R→4, S→2
- D. P→5, Q→3, R→2, S→4
Show answer and solution
Answer: (A) P→1, Q→3, R→2, S→4
(P) is ; is a strong-field ligand, so the configuration is low spin with one unpaired electron: 1.
(Q) is ; is a weak-field ligand, so the complex is high spin with four unpaired electrons 3.
(R) is ; with the strong-field it forms a square planar complex with all electrons paired, hence diamagnetic 2.
(S) With the weak-field , () forms a tetrahedral complex with two unpaired electrons: 4.
No complex in List-I has , so (5) is a distractor. Correct code: P→1, Q→3, R→2, S→4.
(Q) is ; is a weak-field ligand, so the complex is high spin with four unpaired electrons 3.
(R) is ; with the strong-field it forms a square planar complex with all electrons paired, hence diamagnetic 2.
(S) With the weak-field , () forms a tetrahedral complex with two unpaired electrons: 4.
No complex in List-I has , so (5) is a distractor. Correct code: P→1, Q→3, R→2, S→4.
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