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JEE Advanced 2020 Paper 2 · Physics · Kinematics and Laws of Motion · medium

A small ball is projected from the foot of a smooth fixed incline of inclination 30^° with speed 20 m s^-1, in the vertical plane containing the line…

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A small ball is projected from the foot of a smooth fixed incline of inclination 30∘30^\circ with speed 20 m s−120\ \mathrm{m\,s^{-1}}, in the vertical plane containing the line of greatest slope. The velocity of projection makes an angle of 30∘30^\circ with the incline, above it and directed up the slope. Take g=10 m s−2g=10\ \mathrm{m\,s^{-2}} and neglect air resistance. Choose the correct statement(s).
  1. A. The time of flight, until the ball again meets the incline, is 43 s\dfrac{4}{\sqrt3}\ \mathrm{s}.
  2. B. The distance from the point of projection to the point where the ball strikes the incline is 803 m\dfrac{80}{3}\ \mathrm{m}.
  3. C. The ball strikes the incline with its velocity perpendicular to the incline.
  4. D. The maximum perpendicular distance of the ball from the incline is 5 m5\ \mathrm{m}.
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Answer: A, B

Use axes along and perpendicular to the incline. Here g∥=gsin⁡30∘=5g_\parallel=g\sin30^\circ=5 (down the slope) and g⊥=gcos⁡30∘=53g_\perp=g\cos30^\circ=5\sqrt3. The initial components are u∥=20cos⁡30∘=103u_\parallel=20\cos30^\circ=10\sqrt3 and u⊥=20sin⁡30∘=10u_\perp=20\sin30^\circ=10. Time of flight: T=2u⊥g⊥=2053=43 sT=\dfrac{2u_\perp}{g_\perp}=\dfrac{20}{5\sqrt3}=\dfrac{4}{\sqrt3}\ \mathrm{s}, so (A) is true. Range along the slope: R=u∥T−12g∥T2=103⋅43−52⋅163=40−403=803 mR=u_\parallel T-\tfrac12 g_\parallel T^2=10\sqrt3\cdot\dfrac{4}{\sqrt3}-\tfrac52\cdot\dfrac{16}{3}=40-\dfrac{40}{3}=\dfrac{80}{3}\ \mathrm{m}, so (B) is true. At impact the component along the slope is u∥−g∥T=103−203=103≠0u_\parallel-g_\parallel T=10\sqrt3-\dfrac{20}{\sqrt3}=\dfrac{10}{\sqrt3}\neq0, so the velocity is not perpendicular to the incline: (C) is false. Maximum perpendicular distance H=u⊥22g⊥=100103=103≈5.77 mH=\dfrac{u_\perp^2}{2g_\perp}=\dfrac{100}{10\sqrt3}=\dfrac{10}{\sqrt3}\approx5.77\ \mathrm{m}, not 5 m5\ \mathrm{m} (that would come from using gg instead of gcos⁡30∘g\cos30^\circ): (D) is false.
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