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JEE Advanced 2018 Paper 1 · Mathematics · Matrices and Determinants · medium

Let A=beginpmatrix1&1&0\\0&1&1\\0&0&1endpmatrix and let I be the 3×3 identity matrix.

One or more options correct

Let A=(110011001)A=\begin{pmatrix}1&1&0\\0&1&1\\0&0&1\end{pmatrix} and let II be the 3×33\times3 identity matrix. Which of the following statements is (are) correct?
  1. A. The (1,3)(1,3) entry of A10A^{10} equals 4545
  2. B. The (1,3)(1,3) entry of A−1A^{-1} equals −1-1
  3. C. The sum of all nine entries of A4A^{4} equals 1717
  4. D. (A−I)2(A-I)^2 is the zero matrix
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Answer: A, C

Write A=I+NA=I+N with N=(010001000)N=\begin{pmatrix}0&1&0\\0&0&1\\0&0&0\end{pmatrix}, so N2N^2 has a single entry 11 at position (1,3)(1,3) and N3=0N^3=0. Since II and NN commute, An=I+nN+(n2)N2A^n=I+nN+\binom n2N^2. (A) The (1,3)(1,3) entry of A10A^{10} is (102)=45\binom{10}{2}=45, so it is true. (B) A−1=I−N+N2A^{-1}=I-N+N^2 because (I+N)(I−N+N2)=I+N3=I(I+N)(I-N+N^2)=I+N^3=I, hence the (1,3)(1,3) entry is +1+1, not −1-1, so it is false. (C) A4=I+4N+6N2A^4=I+4N+6N^2 has entry sum 3+4⋅2+6⋅1=173+4\cdot2+6\cdot1=17, so it is true. (D) (A−I)2=N2≠0(A-I)^2=N^2\neq0, so the minimal polynomial is (x−1)3(x-1)^3 and the statement is false.
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