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JEE Advanced 2022 Paper 1 · Physics · Thermodynamics and Kinetic Theory of Gases · hard

One mole of a monatomic ideal gas (Cv=3/2R) undergoes the processes in List-I. Match each with its molar heat capacity in List-II. List-I: (P)…

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One mole of a monatomic ideal gas (Cv=32RC_v=\tfrac32R) undergoes the processes in List-I. Match each with its molar heat capacity in List-II.

List-I: (P) PV2=constantPV^2=\text{constant}; (Q) P∝VP\propto V; (R) constant pressure; (S) PV3/2=constantPV^{3/2}=\text{constant}.

List-II (in units of RR): (1) −1/2-1/2; (2) 1/21/2; (3) 3/23/2; (4) 22; (5) 5/25/2.
  1. A. P→1, Q→4, R→5, S→2
  2. B. P→2, Q→3, R→5, S→1
  3. C. P→4, Q→2, R→5, S→1
  4. D. P→2, Q→4, R→5, S→1
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Answer: (D) P→2, Q→4, R→5, S→1

For PVn=constantPV^n=\text{constant}, C=Cv+R1−nC=C_v+\dfrac{R}{1-n}. (P) n=2n=2: 32R−R=12R\tfrac32R-R=\tfrac12R (2). (Q) P∝VP\propto V means n=−1n=-1: 32R+12R=2R\tfrac32R+\tfrac12R=2R (4). (R) isobaric (n=0n=0): 52R\tfrac52R (5). (S) n=32n=\tfrac32: 32R−2R=−12R\tfrac32R-2R=-\tfrac12R (1). So P→2, Q→4, R→5, S→1; List-II entry (3) 3/23/2 (isochoric) is unused.
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