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JEE Main 2021 · Chemistry · Carbonyl Compounds, Carboxylic Acids and Amines · medium

Arrange the following in the correct order of basic strength in aqueous solution: NH3, C2H5NH2, (C2H5)2NH, (C2H5)3N

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Arrange the following in the correct order of basic strength in aqueous solution: NH3\mathrm{NH_3}, C2H5NH2\mathrm{C_2H_5NH_2}, (C2H5)2NH(\mathrm{C_2H_5})_2\mathrm{NH}, (C2H5)3N(\mathrm{C_2H_5})_3\mathrm{N}
  1. A. (C2H5)3N>(C2H5)2NH>C2H5NH2>NH3(\mathrm{C_2H_5})_3\mathrm{N}>(\mathrm{C_2H_5})_2\mathrm{NH}>\mathrm{C_2H_5NH_2}>\mathrm{NH_3}
  2. B. (C2H5)2NH>(C2H5)3N>C2H5NH2>NH3(\mathrm{C_2H_5})_2\mathrm{NH}>(\mathrm{C_2H_5})_3\mathrm{N}>\mathrm{C_2H_5NH_2}>\mathrm{NH_3}
  3. C. (C2H5)2NH>C2H5NH2>(C2H5)3N>NH3(\mathrm{C_2H_5})_2\mathrm{NH}>\mathrm{C_2H_5NH_2}>(\mathrm{C_2H_5})_3\mathrm{N}>\mathrm{NH_3}
  4. D. C2H5NH2>(C2H5)2NH>(C2H5)3N>NH3\mathrm{C_2H_5NH_2}>(\mathrm{C_2H_5})_2\mathrm{NH}>(\mathrm{C_2H_5})_3\mathrm{N}>\mathrm{NH_3}
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Answer: (B) (C2H5)2NH>(C2H5)3N>C2H5NH2>NH3(\mathrm{C_2H_5})_2\mathrm{NH}>(\mathrm{C_2H_5})_3\mathrm{N}>\mathrm{C_2H_5NH_2}>\mathrm{NH_3}

In water, basicity depends on the +I effect of alkyl groups (which stabilises the ammonium ion) and on solvation of the ammonium cation through hydrogen bonding. Each added ethyl group increases electron density on nitrogen, so NH3\mathrm{NH_3} is the weakest. Going from secondary to tertiary, the cation R3NH+R_3NH^+ has only one N–H available for hydrogen bonding and the bulky groups hinder solvation, so the extra +I effect is outweighed. For ethyl groups the observed order is R2NH>R3N>RNH2>NH3\mathrm{R_2NH}>\mathrm{R_3N}>\mathrm{RNH_2}>\mathrm{NH_3} (pKb about 3.0, 3.2, 3.3, 4.7).
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