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JEE Main 2022 · Mathematics · Area Under Curves · medium

If A is the area of the region bounded by the parabola y^2=4x and the line y=x, then 3A equals

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If AA is the area of the region bounded by the parabola y2=4xy^2=4x and the line y=xy=x, then 3A3A equals
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Answer: 8

The curves meet where x2=4xx^2=4x, i.e. x=0x=0 and x=4x=4. Between them y=2xy=2\sqrt x lies above y=xy=x, so A=∫04(2x−x) dx=[43x3/2−x22]04=323−8=83A=\int_0^4(2\sqrt x-x)\,dx=\left[\frac43x^{3/2}-\frac{x^2}2\right]_0^4=\frac{32}3-8=\frac83. Hence 3A=83A=8.
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