PrepRung

JEE Main 2021 · Physics · Atoms, Nuclei and Dual Nature of Radiation · medium

Light of wavelength 200 nm falling on a metal produces photoelectrons whose maximum kinetic energy is three times that obtained with light of…

Numerical answer

Light of wavelength 200 nm200\ \mathrm{nm} falling on a metal produces photoelectrons whose maximum kinetic energy is three times that obtained with light of wavelength 400 nm400\ \mathrm{nm}. Taking hc=1240 eV nmhc=1240\ \mathrm{eV\,nm}, the work function of the metal is x×10−2 eVx\times10^{-2}\ \mathrm{eV}. The value of xx is
Show answer and solution

Answer: 155

Photon energies: 1240200=6.2 eV\dfrac{1240}{200}=6.2\ \mathrm{eV} and 1240400=3.1 eV\dfrac{1240}{400}=3.1\ \mathrm{eV}. Einstein's equation: 6.2−ϕ=3(3.1−ϕ)⇒2ϕ=9.3−6.2=3.1⇒ϕ=1.55 eV=155×10−2 eV6.2-\phi=3(3.1-\phi)\Rightarrow 2\phi=9.3-6.2=3.1\Rightarrow\phi=1.55\ \mathrm{eV}=155\times10^{-2}\ \mathrm{eV}.
Report a mistake

Original question written in the JEE Main 2021 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake