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JEE Main 2020 · Physics · Atoms, Nuclei and Dual Nature of Radiation · easy

Two radioactive samples A and B contain equal numbers of atoms at t = 0. Their half-lives are 1 h and 2 h respectively. The activities of the two…

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Two radioactive samples A and B contain equal numbers of atoms at t=0t = 0. Their half-lives are 1 h1\ \mathrm{h} and 2 h2\ \mathrm{h} respectively. The activities of the two samples will be equal at time
  1. A. 1 h1\ \mathrm{h}
  2. B. 2 h2\ \mathrm{h}
  3. C. 3 h3\ \mathrm{h}
  4. D. 4 h4\ \mathrm{h}
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Answer: (B) 2 h2\ \mathrm{h}

Activity A=λN0e−λtA = \lambda N_0 e^{-\lambda t} with λA=2λB≡2λ\lambda_A = 2\lambda_B \equiv 2\lambda. Equating activities: 2λN0e−2λt=λN0e−λt2\lambda N_0e^{-2\lambda t} = \lambda N_0e^{-\lambda t}, so eλt=2e^{\lambda t} = 2 and t=ln⁡2λ=T1/2(B)=2 ht = \dfrac{\ln 2}{\lambda} = T_{1/2}(B) = 2\ \mathrm{h}. Check: at 2 h2\ \mathrm{h}, NA=N0/4N_A = N_0/4 and NB=N0/2N_B = N_0/2, so AA=2λ⋅N0/4=λN0/2=ABA_A = 2\lambda\cdot N_0/4 = \lambda N_0/2 = A_B. The initial activities are in ratio 2:12:1, so they cross once.
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