PrepRung

JEE Main 2020 · Physics · Fluid Mechanics, Elasticity and Surface Tension · hard

A cylindrical tank of cross-sectional area 0.1 m^2 has a small circular hole of area 10 cm^2 in its base, and water drains out through it. The water…

Numerical answer

A cylindrical tank of cross-sectional area 0.1 m20.1\ \mathrm{m^2} has a small circular hole of area 10 cm210\ \mathrm{cm^2} in its base, and water drains out through it. The water level falls from 1.8 m1.8\ \mathrm{m} to 0.45 m0.45\ \mathrm{m}. Taking g=10 m s−2g = 10\ \mathrm{m\,s^{-2}}, the time taken (in seconds) is
Show answer and solution

Answer: 30

Let the level be hh. Torricelli: outflow speed 2gh\sqrt{2gh}, and continuity gives A dhdt=−a2ghA\,\dfrac{dh}{dt} = -a\sqrt{2gh}. Integrating, t=Aa2g (h1−h2)t = \dfrac{A}{a}\sqrt{\dfrac2g}\,(\sqrt{h_1} - \sqrt{h_2}). With A/a=0.1/10−3=100A/a = 0.1/10^{-3} = 100: t=100×0.2×(1.8−0.45)=100×0.4472×(1.3416−0.6708)=30 st = 100\times\sqrt{0.2}\times(\sqrt{1.8} - \sqrt{0.45}) = 100\times0.4472\times(1.3416 - 0.6708) = 30\ \mathrm{s}.
Report a mistake

Original question written in the JEE Main 2020 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake