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JEE Main 2017 · Physics · Fluid Mechanics, Elasticity and Surface Tension · medium

A large open tank is filled with water to a depth of 5 m and stands on level ground. A small hole made in its side at a depth of 1 m below the free…

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A large open tank is filled with water to a depth of 5 m5\ \mathrm{m} and stands on level ground. A small hole made in its side at a depth of 1 m1\ \mathrm{m} below the free surface throws a horizontal jet that lands at some distance from the tank. A second small hole is made at a different depth so that its jet lands at the same distance. The depth of the second hole below the free surface is
  1. A. 4 m4\ \mathrm{m}
  2. B. 2.5 m2.5\ \mathrm{m}
  3. C. 3 m3\ \mathrm{m}
  4. D. 4.5 m4.5\ \mathrm{m}
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Answer: (A) 4 m4\ \mathrm{m}

By Torricelli's theorem the efflux speed at depth hh is 2gh\sqrt{2gh}. The jet falls through a height H−hH - h (with H=5 mH = 5\ \mathrm{m}) in time 2(H−h)/g\sqrt{2(H-h)/g}, so the range is x=2h(H−h)x = 2\sqrt{h(H-h)}. For h=1 mh = 1\ \mathrm{m}, x=21×4=4 mx = 2\sqrt{1\times4} = 4\ \mathrm{m}. The same xx requires h′(H−h′)=4h'(H - h') = 4, i.e. h′2−5h′+4=0h'^2 - 5h' + 4 = 0, so h′=1 mh' = 1\ \mathrm{m} or 4 m4\ \mathrm{m}. The new hole is therefore at depth 4 m4\ \mathrm{m}, i.e. 1 m1\ \mathrm{m} above the ground. The depth 2.5 m2.5\ \mathrm{m} gives the maximum range, 5 m5\ \mathrm{m}, but not this one.
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