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JEE Main 2023 · Mathematics · Indefinite and Definite Integrals · medium

The value of 16∫0^1 x [4x] dx, where [ · ] denotes the greatest integer function, is

Numerical answer

The value of 16∫01x [4x] dx16\displaystyle\int_0^1 x\,[4x]\,dx, where [ ⋅ ][\,\cdot\,] denotes the greatest integer function, is
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Answer: 17

On [k4,k+14)\left[\frac k4,\frac{k+1}4\right) we have [4x]=k[4x]=k for k=0,1,2,3k=0,1,2,3, so the integral splits into four pieces k∫k/4(k+1)/4x dx=k⋅(k+1)2−k232=k(2k+1)32k\int_{k/4}^{(k+1)/4}x\,dx=k\cdot\frac{(k+1)^2-k^2}{32}=\frac{k(2k+1)}{32}. Evaluating: k=0k=0 gives 00, k=1k=1 gives 332\frac3{32}, k=2k=2 gives 1032\frac{10}{32}, k=3k=3 gives 2132\frac{21}{32}. The sum is 3432\frac{34}{32}, so the integral equals 1716\frac{17}{16} and 1616 times it is 1717.
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