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JEE Main 2021 · Mathematics · Matrices and Determinants · easy

The sum of all the entries of A^25 is

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Let A=[1201]A=\begin{bmatrix}1&2\\0&1\end{bmatrix}. The sum of all the entries of A25A^{25} is
  1. A. 5151
  2. B. 5050
  3. C. 5252
  4. D. 2727
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Answer: (C) 5252

By induction An=[12n01]A^n=\begin{bmatrix}1&2n\\0&1\end{bmatrix}, since multiplying by AA adds 22 to the upper-right entry. So A25=[15001]A^{25}=\begin{bmatrix}1&50\\0&1\end{bmatrix} and the entry sum is 1+50+0+1=521+50+0+1=52.
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