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JEE Main 2019 · Chemistry · s-Block, p-Block Elements and Hydrogen · easy

50 mL of a 6.8% (w/v) solution of hydrogen peroxide is completely decomposed to H2O and O2. Taking R=0.0821 L atm K^-1 mol^-1 and H = 1, O = 16, the…

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50 mL50\ \mathrm{mL} of a 6.8%6.8\% (w/v) solution of hydrogen peroxide is completely decomposed to H2O\mathrm{H_2O} and O2\mathrm{O_2}. Taking R=0.0821 L atm K−1 mol−1R=0.0821\ \mathrm{L\,atm\,K^{-1}\,mol^{-1}} and H = 1, O = 16, the volume of O2\mathrm{O_2} collected at 1 atm1\ \mathrm{atm} and 27 ∘C27\,^\circ\mathrm{C} is nearest to
  1. A. 1.23 L1.23\ \mathrm{L}
  2. B. 2.46 L2.46\ \mathrm{L}
  3. C. 1.12 L1.12\ \mathrm{L}
  4. D. 0.61 L0.61\ \mathrm{L}
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Answer: (A) 1.23 L1.23\ \mathrm{L}

6.8%6.8\% w/v means 6.86.8 g per 100100 mL, so 5050 mL holds 3.43.4 g H2O2\mathrm{H_2O_2} =3.4/34=0.100=3.4/34 = 0.100 mol. 2H2O2→2H2O+O22\mathrm{H_2O_2} \to 2\mathrm{H_2O} + \mathrm{O_2} gives 0.0500.050 mol O2\mathrm{O_2}. V=nRT/P=0.050×0.0821×300/1=1.23 LV = nRT/P = 0.050\times0.0821\times300/1 = 1.23\ \mathrm{L}. Using the STP molar volume (1.12 L1.12\ \mathrm{L}) ignores the stated temperature.
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