The plane z=3 cuts the sphere x^2+y^2+z^2=25 in a circle of radius
Single correct option
The plane z=3 cuts the sphere x2+y2+z2=25 in a circle of radius
A.4
B.5
C.3
D.34
Show answer and solution
Answer:(A) 4
On the plane z=3 the equation becomes x2+y2=25−9=16, a circle of radius 4. The sphere's radius 5 is the trap; the section radius is R2−d2 with d=3 the distance of the centre from the plane.