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NDA 2023 Maths · Mathematics · Continuity and Differentiability · hard

The function f(x)=|x-1| is differentiable at x=1. 2. If f is continuous on [a,b], then f'(c)=0 for some c∈(a,b).

Single correct option

Consider the following statements:
1. The function f(x)=∣x−1∣f(x)=|x-1| is differentiable at x=1x=1.
2. If ff is continuous on [a,b][a,b], then f′(c)=0f'(c)=0 for some c∈(a,b)c\in(a,b).
Which of the statements given above is/are correct?
  1. A. 1 only
  2. B. 2 only
  3. C. Both 1 and 2
  4. D. Neither 1 nor 2
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Answer: (D) Neither 1 nor 2

At x=1x=1 the left derivative is −1-1 and the right derivative is +1+1, so ∣x−1∣|x-1| is not differentiable there; Statement 1 is false. Statement 2 is not true: Rolle's theorem also needs differentiability on (a,b)(a,b) and f(a)=f(b)f(a)=f(b). For example f(x)=xf(x)=x on [0,1][0,1] is continuous but f′f' never vanishes.
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