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NDA 2025 Maths · Mathematics · Differential Equations · medium

If dy/dx=1+y^2 and y(0)=0, then y((π)/(4)) is equal to

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If dydx=1+y2\dfrac{dy}{dx}=1+y^2 and y(0)=0y(0)=0, then y(π4)y\left(\dfrac\pi4\right) is equal to
  1. A. 11
  2. B. 00
  3. C. π4\dfrac\pi4
  4. D. 2\sqrt2
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Answer: (A) 11

Separate variables: dy1+y2=dx\frac{dy}{1+y^2}=dx, so tan⁡−1y=x+C\tan^{-1}y=x+C. From y(0)=0y(0)=0, C=0C=0, so y=tan⁡xy=\tan x and y(π4)=1y\left(\frac\pi4\right)=1. The value π4\frac\pi4 is tan⁡−1y\tan^{-1}y rather than yy, and 00 is the initial value. Verify: ddxtan⁡x=sec⁡2x=1+tan⁡2x\frac{d}{dx}\tan x=\sec^2x=1+\tan^2x.
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