Single correct option
A 12 V battery of negligible internal resistance is connected across resistors of 4 Ω and 2 Ω joined in series. The current in the circuit is
- A. 3 A
- B. 2 A
- C. 6 A
- D. 1.5 A
Show answer and solution
Answer: (B) 2 A
The total resistance in series is 4 + 2 = 6 Ω. By Ohm's law I = V/R = 12/6 = 2 A. The trap is to use only one resistor, which gives 3 A with 4 Ω or 6 A with 2 Ω, or to add the resistors as in parallel.
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