Single correct option
A wire of resistance R is uniformly stretched to double its length. Its new resistance is
- A. 2R
- B. 4R
- C. R/2
- D. R/4
Show answer and solution
Answer: (B) 4R
Stretching keeps the volume constant, so doubling the length halves the cross-sectional area. Resistance = ρL/A therefore becomes ρ(2L)/(A/2) = 4R. Answering 2R forgets the change in area.
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