Single correct option
In a hydraulic press the area of the larger piston is 50 times that of the smaller piston. A force of 100 N applied on the smaller piston can lift a load of
- A. 2 N
- B. 150 N
- C. 50 N
- D. 5000 N
Show answer and solution
Answer: (D) 5000 N
By Pascal's law pressure is transmitted equally, so F2/F1 = A2/A1 = 50. Therefore F2 = 100 x 50 = 5000 N. The press multiplies force, not work: the larger piston moves 50 times less distance. Dividing by 50 gives 2 N, which is the trap.
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