Single correct option
A body of mass 2 kg moving at 3 m/s collides with a stationary body of mass 1 kg and the two stick together. The loss of kinetic energy in the collision is
- A. 6 J
- B. 9 J
- C. 3 J
- D. zero
Show answer and solution
Answer: (C) 3 J
Momentum is conserved: 2 x 3 = (2 + 1) v, so v = 2 m/s. Initial KE = 1/2 x 2 x 9 = 9 J; final KE = 1/2 x 3 x 4 = 6 J. The loss is 9 - 6 = 3 J. The value 6 J is the final energy, not the loss, and zero would apply only to an elastic collision.
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