Single correct option
A simple pendulum has a time period of 2 s on the Earth (a seconds pendulum). If it is taken to the Moon, where g is one-sixth of that on the Earth, its time period will be nearly
- A. 12 s
- B. 0.8 s
- C. 4.9 s
- D. 2 s
Show answer and solution
Answer: (C) 4.9 s
T = 2π√(L/g). If g becomes g/6, T becomes √6 times larger, so T = 2√6 ≈ 4.9 s. The trap is 12 s, which comes from multiplying by 6 instead of √6. The period does depend on g, so it cannot stay 2 s, and a smaller value would mean a stronger field.
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