Single correct option
A projectile is fired at an angle of 45 degrees with the horizontal on level ground. The ratio of its maximum height to its horizontal range is
- A. 1/2
- B. 1/4
- C. 1/8
- D. 1
Show answer and solution
Answer: (B) 1/4
Maximum height H = u^2 sin^2(theta)/(2g) and range R = u^2 sin(2 theta)/g. At 45 degrees, sin^2 is 1/2, so H = u^2/(4g), while R = u^2/g. The ratio H/R is therefore 1/4. In general H/R = tan(theta)/4, which gives 1/4 here because tan 45 = 1.
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