Single correct option
A simple pendulum has a time period T on the Earth. If it is taken to the Moon, where g is one sixth of that on Earth, its time period becomes
- A. 6T
- B. T/√6
- C. T/6
- D. √6 T
Show answer and solution
Answer: (D) √6 T
T = 2π√(L/g). Reducing g to g/6 gives T' = 2π√(6L/g) = √6 T, so the period increases by a factor of about 2.45. Mass does not matter. Writing 6T arises from forgetting the square root, and T/√6 from inverting the dependence on g.
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