Single correct option
The half-life of a radioactive substance is 10 days. The fraction of the original amount remaining after 30 days is
- A. 1/3
- B. 1/8
- C. 1/6
- D. 1/9
Show answer and solution
Answer: (B) 1/8
30 days is three half-lives. The amount left is (1/2)^3 = 1/8. Option 1/3 arises from dividing time linearly, but decay is exponential: each half-life halves the remaining quantity, giving 1/2, 1/4 and then 1/8.
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