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NDA 2023 Maths · Mathematics · Permutations and Combinations · hard

The number of ways of selecting 3 distinct numbers from \1,2,…,20\ such that their sum is divisible by 3 is

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The number of ways of selecting 33 distinct numbers from {1,2,…,20}\{1,2,\dots,20\} such that their sum is divisible by 33 is
  1. A. 342342
  2. B. 360360
  3. C. 384384
  4. D. 400400
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Answer: (C) 384384

Among 11 to 2020 there are 66 numbers with remainder 00, and 77 each with remainders 11 and 22. The sum is divisible by 33 if all three share a remainder or the remainders are 0,1,20,1,2: (63)+(73)+(73)+6⋅7⋅7=20+35+35+294=384\binom63+\binom73+\binom73+6\cdot7\cdot7=20+35+35+294=384.
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