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NDA 2020 Maths · Mathematics · Probability · medium

For events A and B: 1. If A and B are mutually exclusive and both have non-zero probability, they cannot be independent. 2. P(A∪ B)=P(A)+P(B) for any…

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Consider the following statements for events AA and BB:
1. If AA and BB are mutually exclusive and both have non-zero probability, they cannot be independent.
2. P(A∪B)=P(A)+P(B)P(A\cup B)=P(A)+P(B) for any two events AA and BB.
Which of the statements is/are correct?
  1. A. 1 only
  2. B. 2 only
  3. C. Both 1 and 2
  4. D. Neither 1 nor 2
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Answer: (A) 1 only

If A∩B=∅A\cap B=\varnothing then P(A∩B)=0P(A\cap B)=0, but independence needs P(A∩B)=P(A)P(B)>0P(A\cap B)=P(A)P(B)>0 when both are non-zero. These conflict, so such events cannot be independent: statement 1 is correct. Statement 2 omits the term −P(A∩B)-P(A\cap B); the formula holds only for mutually exclusive events. For example, with a die, A={2,4,6}A=\{2,4,6\} and B={1,2}B=\{1,2\} give P(A∪B)=46≠36+26P(A\cup B)=\tfrac46\ne\tfrac36+\tfrac26.
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Original question written in the NDA 2020 Maths pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake