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NDA 2019 Maths · Mathematics · Quadratic Equations · medium

If α,β are the roots of x^2-5x+3=0, the equation whose roots are α+1 and β+1 is

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If α,β\alpha,\beta are the roots of x2−5x+3=0x^2-5x+3=0, the equation whose roots are α+1\alpha+1 and β+1\beta+1 is
  1. A. x2−7x+3=0x^2-7x+3=0
  2. B. x2−5x+9=0x^2-5x+9=0
  3. C. x2−7x+9=0x^2-7x+9=0
  4. D. x2−3x+9=0x^2-3x+9=0
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Answer: (C) x2−7x+9=0x^2-7x+9=0

The new roots are α+1,β+1\alpha+1,\beta+1, so their sum is 5+2=75+2=7 and their product is αβ+(α+β)+1=3+5+1=9\alpha\beta+(\alpha+\beta)+1=3+5+1=9. The equation is x2−7x+9=0x^2-7x+9=0. Equivalently substitute x−1x-1 for xx in the original equation. Keeping the old product 33 is the common slip, as the product changes when each root is shifted.
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