NDA 2023 Maths · Mathematics · Sets, Relations and Functions · medium
Let A⊂ B with n(A)=3 and n(B)=6. The number of sets C such that A⊆ C⊆ B is
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Let A⊂B with n(A)=3 and n(B)=6. The number of sets C such that A⊆C⊆B is
A.6
B.7
C.8
D.64
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Answer:(C) 8
Every such C contains all 3 elements of A and any subset of the remaining 6−3=3 elements of B. Hence the count is 23=8. The trap is to use 26=64 (all subsets of B) or to exclude C=A or C=B, which are both allowed because the inclusions are not strict.