The correct order of the bond angle (central atom) in PH3, NF3, OF2, H2O and NH3 is

Central atoms of the third period ($\mathrm{PH_3}$) use almost pure $p$ orbitals, so its angle is about $93.5^\circ$, the smallest. For $\mathrm{NH_3}$ (lp + 3 bp), the bonded pairs lie close to N, so the angle is large ($107^\circ$); in $\mathrm{NF_3}$ electronegative F pulls the bonding pairs away from N, reducing the bp-bp repulsion ($102.3^\circ$). $\mathrm{H_2O}$ has $104.5^\circ$, while $\mathrm{OF_2}$ has $103.8^\circ$ (F pulls electrons away from O). Order: $\mathrm{PH_3}(93.5)<\mathrm{NF_3}(102.3)<\mathrm{OF_2}(103.8)<\mathrm{H_2O}(104.5)<\mathrm{NH_3}(107)$.