Which pair of species has the same bond order but different magnetic behaviour?

$\mathrm{B_2}$ ($10$ electrons, $\pi_{2p}$ half-filled): bond order $1$, paramagnetic with two unpaired electrons. $\mathrm{O_2^{2-}}$ ($18$ electrons, all MOs filled up to $\pi^*$): bond order $1$, diamagnetic. So the bond orders are equal while magnetism differs. Other pairs: $\mathrm{N_2},\mathrm{CO}$ both order $3$ and diamagnetic; $\mathrm{O_2^-}$ ($1.5$) and $\mathrm{F_2}$ ($1$) differ in order; $\mathrm{N_2^+}$ and $\mathrm{O_2^+}$ both $2.5$ and both paramagnetic.