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NDA 2023 Maths · Mathematics · Binomial Theorem · medium

The value of dbinom121+dbinom123+dbinom125+…+dbinom1211 is

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The value of (121)+(123)+(125)+⋯+(1211)\dbinom{12}{1}+\dbinom{12}{3}+\dbinom{12}{5}+\dots+\dbinom{12}{11} is
  1. A. 10241024
  2. B. 20472047
  3. C. 20482048
  4. D. 40964096
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Answer: (C) 20482048

The sums of binomial coefficients over even and over odd indices are equal, each being half of 212=40962^{12}=4096. So the odd-index sum is 211=20482^{11}=2048. The value 20472047 results from wrongly subtracting the term (120)\binom{12}{0}.
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