PrepRung

NDA 2017 Maths · Mathematics · Continuity and Differentiability · hard

Let f(x)=x^2 for x≤1 and f(x)=ax+b for x>1. If f is differentiable at x=1, then b equals

Single correct option

Let f(x)=x2f(x)=x^2 for x≤1x\le1 and f(x)=ax+bf(x)=ax+b for x>1x>1. If ff is differentiable at x=1x=1, then bb equals
  1. A. 00
  2. B. 11
  3. C. −1-1
  4. D. 22
Show answer and solution

Answer: (C) −1-1

Continuity gives a+b=1a+b=1. Differentiability needs equal slopes: a=2a=2 (the derivative of x2x^2 at 11). Hence b=1−2=−1b=1-2=-1. The value 11 is a+ba+b, which continuity alone gives, and 22 is aa.
Report a mistake

Original question written in the NDA 2017 Maths pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake