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The value of ∫0^1(2x+3) dx is Single correct option
The value of
∫ 0 1 ( 2 x + 3 ) d x \displaystyle\int_0^1(2x+3)\,dx ∫ 0 1 ( 2 x + 3 ) d x is
A. 3 3 3 B. 4 4 4 C. 5 5 5 D. 2 2 2 Show answer and solution Answer: (B) 4 4 4
∫ 0 1 ( 2 x + 3 ) d x = [ x 2 + 3 x ] 0 1 = 1 + 3 = 4 \int_0^1(2x+3)dx=\left[x^2+3x\right]_0^1=1+3=4 ∫ 0 1 ( 2 x + 3 ) d x = [ x 2 + 3 x ] 0 1 = 1 + 3 = 4 . Trap: integrating only the variable term gives 1, only the constant gives 3, and forgetting to halve when raising the power (
∫ x d x = x 2 2 \int x\,dx=\frac{x^2}{2} ∫ x d x = 2 x 2 with coefficient 2) can lead to 5.
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