Single correct optionThe solution set of log1/2(x−1)>1\log_{1/2}(x-1)>1log1/2(x−1)>1 isA. x>32x>\dfrac32x>23B. 1<x<321<x<\dfrac321<x<23C. x>1x>1x>1D. 0<x<320<x<\dfrac320<x<23Show answer and solutionAnswer: (B) 1<x<321<x<\dfrac321<x<23The domain requires x>1x>1x>1. Since the base 12\tfrac1221 is less than 1, the logarithm is a decreasing function, so the inequality reverses: x−1<(12)1=12x-1<(\tfrac12)^1=\tfrac12x−1<(21)1=21. Together, 1<x<321<x<\tfrac321<x<23. Option x>32x>\tfrac32x>23 is what results if the reversal is forgotten.SaveMy notesReport a mistakeMy notes on this pageSaved on this device. Sign in or create a free account to keep it on every device.← Previous Logarithms questionNext Logarithms question →