Single correct option
A freely falling body starting from rest covers distances in successive equal seconds in the ratio
- A. 1 : 2 : 3
- B. 1 : 4 : 9
- C. 1 : 1 : 1
- D. 1 : 3 : 5
Show answer and solution
Answer: (D) 1 : 3 : 5
From s = (1/2)gt², distance in the nth second is (g/2)(2n − 1), giving the ratio 1 : 3 : 5 for the first three seconds. The ratio 1 : 4 : 9 is for total distances from the start, not for distances in each successive second, which is the usual trap. Equal distances would mean constant speed.
Saved on this device. Sign in or create a free account to keep it on every device.