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NDA 2020 Maths · Mathematics · Sets, Relations and Functions · medium

If n(A)=40, n(B)=35, n(C)=30, n(A∩ B)=15, n(B∩ C)=10, n(C∩ A)=12 and n(A∩ B∩ C)=5, then n(A∪ B∪ C) is

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If n(A)=40n(A)=40, n(B)=35n(B)=35, n(C)=30n(C)=30, n(A∩B)=15n(A\cap B)=15, n(B∩C)=10n(B\cap C)=10, n(C∩A)=12n(C\cap A)=12 and n(A∩B∩C)=5n(A\cap B\cap C)=5, then n(A∪B∪C)n(A\cup B\cup C) is
  1. A. 78
  2. B. 73
  3. C. 68
  4. D. 83
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Answer: (B) 73

Use inclusion-exclusion: n(A∪B∪C)=105−(15+10+12)+5=105−37+5=73n(A\cup B\cup C)=105-(15+10+12)+5=105-37+5=73. Forgetting to add back the triple intersection gives 68, a common slip, while 78 results from adding it twice.
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