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JEE Main 2017 · Mathematics · Differentiation and Application of Derivatives · medium

For the function y=x^x defined on x>0, the value of its derivative at the point x=1 is

Single correct option

For the function y=xxy=x^x defined on x>0x>0, the value of its derivative at the point x=1x=1 is
  1. A. 00
  2. B. 11
  3. C. 22
  4. D. ee
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Answer: (B) 11

Take logarithms: ln⁡y=xln⁡x\ln y=x\ln x. Differentiate to get 1ydydx=ln⁡x+1\dfrac1y\dfrac{dy}{dx}=\ln x+1, so dydx=xx(1+ln⁡x)\dfrac{dy}{dx}=x^x(1+\ln x). At x=1x=1 this is 1⋅(1+0)=11\cdot(1+0)=1. Treating xxx^x as a power function would wrongly give x⋅xx−1=1x\cdot x^{x-1}=1 only by coincidence at this point, so the logarithmic method is the safe one.
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