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JEE Main 2017 · Mathematics · Matrices and Determinants · easy

If A=beginbmatrix1&2\\3&4endbmatrix, then det (A^3 equals

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If A=[1234]A=\begin{bmatrix}1&2\\3&4\end{bmatrix}, then det⁡(A3)\det(A^3) equals
  1. A. 88
  2. B. −8-8
  3. C. −6-6
  4. D. −2-2
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Answer: (B) −8-8

The determinant is multiplicative: det⁡(A3)=(det⁡A)3\det(A^3)=(\det A)^3. Here det⁡A=1⋅4−2⋅3=−2\det A=1\cdot4-2\cdot3=-2, so det⁡(A3)=(−2)3=−8\det(A^3)=(-2)^3=-8. Computing A3A^3 explicitly is unnecessary. The distractor −6-6 cubes incorrectly while 88 ignores the sign of the determinant.
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