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NDA 2023 Maths · Mathematics · Straight Lines · easy

The equation of the line through (1,2) perpendicular to 2x-3y+5=0 is

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The equation of the line through (1,2)(1,2) perpendicular to 2x−3y+5=02x-3y+5=0 is
  1. A. 2x−3y=−42x-3y=-4
  2. B. 3x−2y=−13x-2y=-1
  3. C. 3x+2y=73x+2y=7
  4. D. 2x+3y=82x+3y=8
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Answer: (C) 3x+2y=73x+2y=7

The given line has slope 23\tfrac23, so the perpendicular has slope −32-\tfrac32. Through (1,2)(1,2): y−2=−32(x−1)y-2=-\tfrac32(x-1), i.e. 3x+2y=73x+2y=7. The option 2x−3y=−42x-3y=-4 is the line parallel to the given one through (1,2)(1,2), a typical trap.
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