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NDA 2022 Maths · Mathematics · Straight Lines · easy

The distance of the point (1,2) from the line 3x+4y-5=0 is

Single correct option

The distance of the point (1,2)(1,2) from the line 3x+4y−5=03x+4y-5=0 is
  1. A. 65\dfrac65
  2. B. 66
  3. C. 115\dfrac{11}{5}
  4. D. 15\dfrac15
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Answer: (A) 65\dfrac65

Distance =∣3(1)+4(2)−5∣32+42=65=\frac{|3(1)+4(2)-5|}{\sqrt{3^2+4^2}}=\frac65. Forgetting to divide by a2+b2\sqrt{a^2+b^2} gives 66; adding the constant instead of subtracting gives 115\frac{11}{5}-type errors.
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Original question written in the NDA 2022 Maths pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake