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The line through (-2,5) parallel to 3x-2y+7=0 is Single correct option
The line through
( − 2 , 5 ) (-2,5) ( − 2 , 5 ) parallel to
3 x − 2 y + 7 = 0 3x-2y+7=0 3 x − 2 y + 7 = 0 is
A. 3 x − 2 y − 16 = 0 3x-2y-16=0 3 x − 2 y − 16 = 0 B. 2 x + 3 y − 11 = 0 2x+3y-11=0 2 x + 3 y − 11 = 0 C. 3 x − 2 y + 4 = 0 3x-2y+4=0 3 x − 2 y + 4 = 0 D. 3 x − 2 y + 16 = 0 3x-2y+16=0 3 x − 2 y + 16 = 0 Show answer and solution Answer: (D) 3 x − 2 y + 16 = 0 3x-2y+16=0 3 x − 2 y + 16 = 0
A parallel line keeps the same
x , y x,y x , y coefficients:
3 x − 2 y + k = 0 3x-2y+k=0 3 x − 2 y + k = 0 . Substituting
( − 2 , 5 ) (-2,5) ( − 2 , 5 ) :
− 6 − 10 + k = 0 -6-10+k=0 − 6 − 10 + k = 0 , so
k = 16 k=16 k = 16 . The line
2 x + 3 y − 11 = 0 2x+3y-11=0 2 x + 3 y − 11 = 0 is perpendicular to the given line, not parallel.
Original question written in the NDA 2021 Maths pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake