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CAT 2018 Slot 1 · Quant · Logarithms and Indices · easy

If log₃x + log₉x + log₂₇x = 22/3, then x equals

Single correct option

If log₃x + log₉x + log₂₇x = 22/3, then x equals
  1. A. 81
  2. B. 27
  3. C. 9
  4. D. 243
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Answer: (A) 81

Convert everything to base 3: log₉x = (log₃x)/2 and log₂₇x = (log₃x)/3.

So log₃x (1 + 1/2 + 1/3) = (11/6) log₃x = 22/3, giving log₃x = (22/3) × (6/11) = 4.

Hence x = 3⁴ = 81.

Tip: log_{bⁿ} x = (1/n) log_b x — always change to the smallest common base.
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Original question written in the CAT 2018 Slot 1 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake